Question

3．計(jì)算$\sqrt{12}$÷$\sqrt{\frac{27}{2}}$×$\sqrt{\frac{1}{36}}$的值為（　�。�

• A． $\sqrt{3}$
• B． $\frac{3}{2}$$\sqrt{2}$
• C． $\frac{\sqrt{2}}{9}$
• D． $\frac{3}{2}$

Answer 1

分析 根據(jù)二次根式的乘除法法則進(jìn)行計(jì)算即可．

解答 解：$\sqrt{12}$÷$\sqrt{\frac{27}{2}}$×$\sqrt{\frac{1}{36}}$
=$\sqrt{12÷\frac{27}{2}×\frac{1}{36}}$
=$\sqrt{\frac{2}{81}}$
=$\frac{\sqrt{2}}{9}$．
故答案選C．

點(diǎn)評(píng) 此題主要考查二次根式的乘除運(yùn)算，熟悉二次根式的乘除運(yùn)算法則并進(jìn)行準(zhǔn)確計(jì)算和化簡(jiǎn)是解題的關(guān)鍵．