Question

如圖，數(shù)1對(duì)應(yīng)著1顆星形，數(shù)2對(duì)應(yīng)著5顆星形，數(shù)3對(duì)應(yīng)著9顆星形，…，按這樣的規(guī)律排列下去，則正整數(shù)n
對(duì)應(yīng)著

 

顆星形．

Answer 1

考點(diǎn)：規(guī)律型：圖形的變化類

專題：

分析：由數(shù)1對(duì)應(yīng)著1顆星形，數(shù)2對(duì)應(yīng)著4+1=5顆星形，數(shù)3對(duì)應(yīng)著4×2+1=9顆星形，數(shù)4對(duì)應(yīng)著4×3+1=13顆星形…，得出正整數(shù)n對(duì)應(yīng)著4（n-1）+1=4n-3顆星形，由此得出答案即可．

解答：解：∵數(shù)1對(duì)應(yīng)著1顆星形，
數(shù)2對(duì)應(yīng)著4+1=5顆星形，
數(shù)3對(duì)應(yīng)著4×2+1=9顆星形，
數(shù)4對(duì)應(yīng)著4×3+1=13顆星形，
…，
正整數(shù)n對(duì)應(yīng)著4（n-1）+1=4n-3顆星形．
故答案為：4n-3．

點(diǎn)評(píng)：此題考查圖形的變化規(guī)律，找出圖形之間的聯(lián)系，得出數(shù)字的運(yùn)算規(guī)律，利用規(guī)律解決問題．