題目列表(包括答案和解析)
已知等比數(shù)列{an}的公比為q,記bn=am(n-1)+1+am(n-1)+2+…+am(n-1)+m,cn=am(n-1)+1·am(n-1)+2·…·am(n-1)+m(m,n∈N*),則以下結(jié)論一定正確的是( )
A.?dāng)?shù)列{bn}為等差數(shù)列,公差為qm
B.?dāng)?shù)列{bn}為等比數(shù)列,公比為q2m
C.?dāng)?shù)列{cn}為等比數(shù)列,公比為qm2
D.?dāng)?shù)列{cn}為等比數(shù)列,公比為qmm
已知等比數(shù)列{an}的公比為q,記bn=am(n-1)+1+am(n-1)+2+…+am(n-1)+m,cn=am(n-1)+1·am(n-1)+2·…·am(n-1)+m(m,n∈N*),則以下結(jié)論一定正確的是( )
A.?dāng)?shù)列{bn}為等差數(shù)列,公差為qm
B.?dāng)?shù)列{bn}為等比數(shù)列,公比為q2m
C.?dāng)?shù)列{cn}為等比數(shù)列,公比為qm2
D.?dāng)?shù)列{cn}為等比數(shù)列,公比為qmn
已知等比數(shù)列{an}的公比為q,記bn=am(n-1)+1+am(n-1)+2+…+am(n-1)+m,cn=am(n-1)+1·am(n-1)+2·…·am(n-1)+m(m,n∈N*),則以下結(jié)論一定正確的是( ).
A.?dāng)?shù)列{bn}為等差數(shù)列,公差為qm
B.?dāng)?shù)列{bn}為等比數(shù)列,公比為q2m
C.?dāng)?shù)列{cn}為等比數(shù)列,公比為qm2
D.?dāng)?shù)列{cn}為等比數(shù)列,公比為qmn
| A.?dāng)?shù)列{bn}為等差數(shù)列,公差為qm |
| B.?dāng)?shù)列{bn}為等比數(shù)列,公比為q2m |
| C.?dāng)?shù)列{cn}為等比數(shù)列,公比為qm2 |
| D.?dāng)?shù)列{cn}為等比數(shù)列,公比為qmm |
已知等比數(shù)列{an}的公比為q,前n項(xiàng)和為Sn,且S3,S9,S6成等差數(shù)列,則q3等于
A.1
B.-![]()
C.-1或![]()
D.1或-![]()
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