1、(2009年全國卷Ⅰ)19.天文學家新發(fā)現了太陽系外的一顆行星。這顆行星的體積是地球的4.7倍,質量是地球的25倍,已知某一近地衛(wèi)星繞地球運動的周期約為1.4小時,引力常量G=6.67×10-11N·m2/kg2,由此佑算該行星的平均密度約為
A.1.8×103kg/m3 B.5.6×103kg/m3 C.1.1×104kg/m3 D.2.9×104kg/m3
答案D
[解析]本題考查天體運動的知識.首先根據近地衛(wèi)星饒地球運動的向心力由萬有引力提供
,可求出地球的質量.然后根據
,可得該行星的密度約為2.9×104kg/m3
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