Question

任何兩個(gè)奇數(shù)的和一定是（　�。�

A．奇數(shù)

B．偶數(shù)

C．質(zhì)數(shù)

D．合數(shù)

Answer 1

分析：根據(jù)奇數(shù)和偶數(shù)的性質(zhì)：兩個(gè)偶數(shù)的和或差仍是偶數(shù)，兩個(gè)奇數(shù)的和或差也是偶數(shù)，奇數(shù)和偶數(shù)的和或差是奇數(shù)；由此解答即可．

解答：解：根據(jù)分析可知：奇數(shù)+奇數(shù)=偶數(shù)；
答：任何兩個(gè)奇數(shù)的和一定是偶數(shù)．
故選：B．

點(diǎn)評(píng)：此題主要根據(jù)奇數(shù)和偶數(shù)的性質(zhì)進(jìn)行解答．