解:(1)200.9×10%+2.009×490+0.2009×5000,
=200.9×0.1+200.9×4.9+200.9×5,
=200.9×(0.1+4.9+5),
=200.9×10,
=2009;
(2)[

-(

-

)]×

,
=[

-

]×

,
=[

]×

,
=

,
=

;
(3)(

+

+

)×24,
=


24

24,
=10+6+9,
=25;
(4)

+

+

+

+

+

+

+

,
=(1

)+(

)+(

)+(

)+(

)+(

)+(

)+(

),
=1-

,
=

.
分析:(1)200.9×10%+2.009×490+0.2009×5000,首先根據(jù)積的變化規(guī)律,一個因數(shù)擴(kuò)大10倍、100倍…,另一個因數(shù)縮小10倍、100倍…,積不變,原式轉(zhuǎn)化為200.9×0.1+200.9×4.9+200.9×5,再應(yīng)用乘法分配律進(jìn)行簡算;
(2)[

-(

-

)]×

,根據(jù)分?jǐn)?shù)四則混合運(yùn)算的運(yùn)算順序,按照它們的計算法則直接進(jìn)行計算;
(3)(

+

+

)×24,應(yīng)用乘法分配律進(jìn)行簡算;
(4)

+

+

+

+

+

+

+

.根據(jù)分?jǐn)?shù)的拆分原理和方法,把每個分?jǐn)?shù)拆分成兩個單位分?jǐn)?shù)的差,相互抵消,這樣計算比較簡便.
點(diǎn)評:此題主要考查應(yīng)用整數(shù)的運(yùn)算定律和分?jǐn)?shù)的拆分方法,對分?jǐn)?shù)、小數(shù)四則混合運(yùn)算進(jìn)行簡便計算.