Question

10．已知$\left\{\begin{array}{l}{x=0}\\{y=-0.5}\end{array}\right.$是方程組$\left\{\begin{array}{l}{x-b=y}\\{5x-2a=2y}\end{array}\right.$的解，求a，b的值．

Answer 1

分析 直接把x、y的值代入方程組，求出a、b的值即可．

解答 解：∵$\left\{\begin{array}{l}{x=0}\\{y=-0.5}\end{array}\right.$是方程組$\left\{\begin{array}{l}{x-b=y}\\{5x-2a=2y}\end{array}\right.$的解，
∴$\left\{\begin{array}{l}0-b=-0.5\\ 0-2a=-1\end{array}\right.$，
解得a=$\frac{1}{2}$，b=0.5．

點評 本題考查的是二元一次方程組的解，熟知二元一次方程組的解一定適合此方程組是解答此題的關(guān)鍵．