Question

13．單項(xiàng)式-$\frac{a^{2}}{5}$的系數(shù)是m，多項(xiàng)式2a²b³+3b²c²-1的次數(shù)是n，則m+n=$\frac{24}{5}$．

Answer 1

分析 根據(jù)單項(xiàng)式系數(shù)的定義和多項(xiàng)式次數(shù)的定義求解即可．

解答 解：∵單項(xiàng)式-$\frac{a^{2}}{5}$的系數(shù)是-$\frac{1}{5}$，
∴m=-$\frac{1}{5}$，
∵多項(xiàng)式2a²b³+3b²c²-1的次數(shù)是5，
∴n=5，則m+n=$\frac{24}{5}$．
故答案為：$\frac{24}{5}$．

點(diǎn)評(píng) 本題考查了多項(xiàng)式和單項(xiàng)式，解答本題的關(guān)鍵是掌握單項(xiàng)式系數(shù)的定義和多項(xiàng)式次數(shù)的定義．