Question

10．如圖，直線AB的關(guān)系式為0.5x-y=-2，直線CD的關(guān)系式為2x-y=4，點(diǎn)D為兩條直線的交點(diǎn)，則方程$\left\{\begin{array}{l}{0.5x-y=-2}\\{2x-y=4}\end{array}\right.$的解為（　�。�

• A． $\left\{\begin{array}{l}{x=0}\\{y=-4}\end{array}\right.$
• B． $\left\{\begin{array}{l}{x=0}\\{y=2}\end{array}\right.$
• C． $\left\{\begin{array}{l}{x=-4}\\{y=0}\end{array}\right.$
• D． $\left\{\begin{array}{l}{x=4}\\{y=4}\end{array}\right.$

Answer 1

分析 利用函數(shù)圖象交點(diǎn)坐標(biāo)為兩函數(shù)解析式組成的方程組的解進(jìn)行判斷．

解答 解：因?yàn)橹本�0.5x-y=-2與直線2x-y=4的交點(diǎn)D的坐標(biāo)為（4，4），
所以方程$\left\{\begin{array}{l}{0.5x-y=-2}\\{2x-y=4}\end{array}\right.$的解為$\left\{\begin{array}{l}{x=4}\\{y=4}\end{array}\right.$．
故選D．

點(diǎn)評(píng) 本題考查了一次函數(shù)解析與二元一次方程（組）：函數(shù)圖象交點(diǎn)坐標(biāo)為兩函數(shù)解析式組成的方程組的解．