Question

12．一次函數(shù)y=3-x與y=3x-5的圖象的交點(diǎn)為（2，1），則方程組$\left\{\begin{array}{l}{x+y=3}\\{3x-y=5}\end{array}\right.$的解為$\left\{\begin{array}{l}{x=2}\\{y=1}\end{array}\right.$．

Answer 1

分析 根據(jù)兩函數(shù)交點(diǎn)即為兩函數(shù)組成的方程組的解，從而求出答案．

解答 解：∵一次函數(shù)y=3-x與y=3x-5的圖象的交點(diǎn)為（2，1），
∴方程組$\left\{\begin{array}{l}{x+y=3}\\{3x-y=5}\end{array}\right.$的解為$\left\{\begin{array}{l}{x=2}\\{y=1}\end{array}\right.$．
故答案為$\left\{\begin{array}{l}{x=2}\\{y=1}\end{array}\right.$．

點(diǎn)評(píng) 本題考查了一次函數(shù)與二元一次方程組交點(diǎn)問(wèn)題，可直接根據(jù)交點(diǎn)寫(xiě)出．