Question

13．多項(xiàng)式2+4x²y-$\frac{1}{3}$x²y³是2，4x²y，-$\frac{1}{3}$x²y³三項(xiàng)的和，其中次數(shù)最高項(xiàng)的系數(shù)是-$\frac{1}{3}$．

Answer 1

分析 根據(jù)多項(xiàng)式的定義以及多項(xiàng)式的次數(shù)進(jìn)行填空即可．

解答 解：多項(xiàng)式2+4x²y-$\frac{1}{3}$x²y³的項(xiàng)是2，4x²y，$-\frac{1}{3}{x^2}{y^3}$，單項(xiàng)式的次數(shù)是$-\frac{1}{3}$．
故答案為2，4x²y，$-\frac{1}{3}{x^2}{y^3}$，$-\frac{1}{3}$．

點(diǎn)評(píng) 本題考查了多項(xiàng)式，掌握多項(xiàng)式的項(xiàng)、次數(shù)是解題的關(guān)鍵．