Question

12．計(jì)算：$\frac{\frac{7}{16}×2\frac{2}{3}+\frac{1}{7}}{12\frac{1}{3}-3\frac{3}{4}÷\frac{5}{14}}$×1$\frac{10}{11}$．

Answer 1

分析 根據(jù)有理數(shù)混合計(jì)算的順序進(jìn)行解答即可．

解答 解：$\frac{\frac{7}{16}×2\frac{2}{3}+\frac{1}{7}}{12\frac{1}{3}-3\frac{3}{4}÷\frac{5}{14}}×1\frac{10}{11}$
=$\frac{\frac{7}{16}×\frac{8}{3}+\frac{1}{7}}{12\frac{1}{3}-\frac{15}{4}×\frac{14}{5}}×\frac{21}{11}$
=$\frac{\frac{7}{6}+\frac{1}{7}}{12\frac{1}{3}-10\frac{1}{2}}×\frac{21}{11}$
=$\frac{\frac{55}{42}}{\frac{11}{6}}×\frac{21}{11}$
=$\frac{5}{7}×\frac{21}{11}$
=$\frac{15}{11}$

點(diǎn)評(píng) 此題考查有理數(shù)混合計(jì)算，關(guān)鍵是根據(jù)有理數(shù)混合計(jì)算順序進(jìn)行計(jì)算．