Question

8．$\sqrt{2}$-1的相反數(shù)是1-$\sqrt{2}$，$\sqrt{2}$-1的絕對(duì)值是$\sqrt{2}$-1，$\sqrt{2}$-1的倒數(shù)是$\sqrt{2}$+1．

Answer 1

分析 根據(jù)相反數(shù)的意義，絕對(duì)值的性質(zhì)，乘積為1的倒數(shù)，可得答案．

解答 解：$\sqrt{2}$-1的相反數(shù)是 1-$\sqrt{2}$，$\sqrt{2}$-1的絕對(duì)值是 $\sqrt{2}$-1，$\sqrt{2}$-1的倒數(shù)是 $\sqrt{2}$+1，
故答案為：1-$\sqrt{2}$，$\sqrt{2}$-1，$\sqrt{2}$+1．

點(diǎn)評(píng) 本題考查了實(shí)數(shù)的性質(zhì)，利用相反數(shù)的意義，絕對(duì)值的性質(zhì)，乘積為1的倒數(shù)是解題關(guān)鍵．